A veces es conveniente tener nombres de variables variables. Dicho de otro modo, son nombres de variables que se pueden definir y usar dinámicamente. Una variable normal se establece con una sentencia como:
<?php
$a = 'hola';
?>Una variable variable toma el valor de una variable y lo trata como el nombre de una variable. En el ejemplo anterior, hola, se puede usar como el nombre de una variable utilizando dos signos de dólar. Es decir:
<?php
$$a = 'mundo';
?>En este momento se han definido y almacenado dos variables en el árbol de símbolos de PHP: $a, que contiene "hola", y $hola, que contiene "mundo". Es más, esta sentencia:
<?php
echo "$a ${$a}";
?>produce el mismo resultado que:
<?php
echo "$a $hola";
?>esto quiere decir que ambas producen el resultado: hola mundo.
Para usar variables variables con arrays hay que resolver un problema de ambigüedad. Si se escribe $$a[1], el intérprete necesita saber si nos referimos a utilizar $a[1] como una variable, o si se pretendía utilizar $$a como variable y el índice [1] como índice de dicha variable. La sintaxis para resolver esta ambigüedad es: ${$a[1]} para el primer caso y ${$a}[1] para el segundo.
También se puede acceder a las propiedades de una clase usando el nombre de propiedad variable. Este será resuelto dentro del ámbito del cual se hizo la llamada. Por ejemplo, en la expresión $foo->$bar, se buscará $bar en el ámibto local y se empleará su valor será como el nombre de la propiedad de $foo. Esto también es cierto si $bar es un acceso a un array.
También se pueden usar llaves para delimitar de forma clara el nombre de la propiedad. Son muy útila al acceder a valores dentro una propiedad que contiene un array, cuando el nombre de la propiedad está compuesto de múltiples partes, o cuando el nombre de la propiedad contiene caracteres que de otro modo no son válidos (p.ej. desde json_decode() o SimpleXML).
Ejemplo #1 Ejemplo de propiedad variable
<?php
class foo {
var $bar = 'Soy bar.';
var $arr = array('Soy A.', 'Soy B.', 'Soy C.');
var $r = 'Soy r.';
}
$foo = new foo();
$bar = 'bar';
$baz = array('foo', 'bar', 'baz', 'quux');
echo $foo->$bar . "\n";
echo $foo->{$baz[1]} . "\n";
$start = 'b';
$end = 'ar';
echo $foo->{$start . $end} . "\n";
$arr = 'arr';
echo $foo->{$arr[1]} . "\n";
echo $foo->{$arr}[1] . "\n";
?>El ejemplo anterior mostrará:
Por favor tenga en cuenta que las variables variables no pueden usarse
con los Arrays
superglobales de PHP al interior de funciones o métodos de
clase. La variable $this es también una variable
especial que no puede ser referenciada dinámicamente.
<?php
//You can even add more Dollar Signs
$Bar = "a";
$Foo = "Bar";
$World = "Foo";
$Hello = "World";
$a = "Hello";
$a; //Returns Hello
$$a; //Returns World
$$$a; //Returns Foo
$$$$a; //Returns Bar
$$$$$a; //Returns a
$$$$$$a; //Returns Hello
$$$$$$$a; //Returns World
//... and so on ...//
?>In addition, it is possible to use associative array to secure name of variables available to be used within a function (or class / not tested).
This way the variable variable feature is useful to validate variables; define, output and manage only within the function that receives as parameter
an associative array :
array('index'=>'value','index'=>'value');
index = reference to variable to be used within function
value = name of the variable to be used within function
<?php
$vars = ['id'=>'user_id','email'=>'user_email'];
validateVarsFunction($vars);
function validateVarsFunction($vars){
//$vars['id']=34; <- does not work
// define allowed variables
$user_id=21;
$user_email='email@mail.com';
echo $vars['id']; // prints name of variable: user_id
echo ${$vars['id']}; // prints 21
echo 'Email: '.${$vars['email']}; // print email@mail.com
// we don't have the name of the variables before declaring them inside the function
}
?>It may be worth specifically noting, if variable names follow some kind of "template," they can be referenced like this:
<?php
// Given these variables ...
$nameTypes = array("first", "last", "company");
$name_first = "John";
$name_last = "Doe";
$name_company = "PHP.net";
// Then this loop is ...
foreach($nameTypes as $type)
print ${"name_$type"} . "\n";
// ... equivalent to this print statement.
print "$name_first\n$name_last\n$name_company\n";
?>
This is apparent from the notes others have left, but is not explicitly stated.The feature of variable variable names is welcome, but it should be avoided when possible. Modern IDE software fails to interpret such variables correctly, regular find/replace also fails. It's a kind of magic :) This may really make it hard to refactor code. Imagine you want to rename variable $username to $userName and try to find all occurrences of $username in code by checking "$userName". You may easily omit:
$a = 'username';
echo $$a;If you want to use a variable value in part of the name of a variable variable (not the whole name itself), you can do like the following:
<?php
$price_for_monday = 10;
$price_for_tuesday = 20;
$price_for_wednesday = 30;
$today = 'tuesday';
$price_for_today = ${ 'price_for_' . $today};
echo $price_for_today; // will return 20
?>One interesting thing I found out: You can concatenate variables and use spaces. Concatenating constants and function calls are also possible.
<?php
define('ONE', 1);
function one() {
return 1;
}
$one = 1;
${"foo$one"} = 'foo';
echo $foo1; // foo
${'foo' . ONE} = 'bar';
echo $foo1; // bar
${'foo' . one()} = 'baz';
echo $foo1; // baz
?>
This syntax doesn't work for functions:
<?php
$foo = 'info';
{"php$foo"}(); // Parse error
// You'll have to do:
$func = "php$foo";
$func();
?>
Note: Don't leave out the quotes on strings inside the curly braces, PHP won't handle that graciously.While not relevant in everyday PHP programming, it seems to be possible to insert whitespace and comments between the dollar signs of a variable variable. All three comment styles work. This information becomes relevant when writing a parser, tokenizer or something else that operates on PHP syntax.
<?php
$foo = 'bar';
$
/*
I am complete legal and will compile without notices or error as a variable variable.
*/
$foo = 'magic';
echo $bar; // Outputs magic.
?>
Behaviour tested with PHP Version 5.6.19PHP actually supports invoking a new instance of a class using a variable class name since at least version 5.2
<?php
class Foo {
public function hello() {
echo 'Hello world!';
}
}
$my_foo = 'Foo';
$a = new $my_foo();
$a->hello(); //prints 'Hello world!'
?>
Additionally, you can access static methods and properties using variable class names, but only since PHP 5.3
<?php
class Foo {
public static function hello() {
echo 'Hello world!';
}
}
$my_foo = 'Foo';
$my_foo::hello(); //prints 'Hello world!'
?>Variable Class Instantiation with Namespace Gotcha:
Say you have a class you'd like to instantiate via a variable (with a string value of the Class name)
<?php
class Foo
{
public function __construct()
{
echo "I'm a real class!" . PHP_EOL;
}
}
$class = 'Foo';
$instance = new $class;
?>
The above works fine UNLESS you are in a (defined) namespace. Then you must provide the full namespaced identifier of the class as shown below. This is the case EVEN THOUGH the instancing happens in the same namespace. Instancing a class normally (not through a variable) does not require the namespace. This seems to establish the pattern that if you are using an namespace and you have a class name in a string, you must provide the namespace with the class for the PHP engine to correctly resolve (other cases: class_exists(), interface_exists(), etc.)
<?php
namespace MyNamespace;
class Foo
{
public function __construct()
{
echo "I'm a real class!" . PHP_EOL;
}
}
$class = 'MyNamespace\Foo';
$instance = new $class;
?>These are the scenarios that you may run into trying to reference superglobals dynamically. Whether or not it works appears to be dependent upon the current scope.
<?php
$_POST['asdf'] = 'something';
function test() {
// NULL -- not what initially expected
$string = '_POST';
var_dump(${$string});
// Works as expected
var_dump(${'_POST'});
// Works as expected
global ${$string};
var_dump(${$string});
}
// Works as expected
$string = '_POST';
var_dump(${$string});
test();
?>